URI Online Judge | 1035 Selection Test (Solution)

Problem Link:
https://www.urionlinejudge.com.br/judge/en/problems/view/1035

URI Online Judge | 1035

Selection Test 1

Adapted by Neilor Tonin, URI  Brazil
Timelimit: 1
Read 4 integer numbers A, B, C and D. Then if B is greater than C and D is greater than A and if the sum of C and D is greater than the sum of A and B and if C and D were positives values and if A is even, write the message “Valores aceitos” (Accepted values). Otherwise, write the message “Valores nao aceitos” (Values not accepted).

Input

Four integer numbers A, B, C and D.

Output

Show the corresponding message after the validation of the values​​.
Sample InputSample Output
5 6 7 8Valores nao aceitos
2 3 2 6Valores aceitos
Solution:
#include<stdio.h>
int main()
{
    int a,b,c,d;
    scanf("%d %d %d %d",&a,&b,&c,&d);
    if(b>c&&d>a&&((c+d)>(a+b))&&(c&&d)>=0&&a%2==0)
    {
        printf("Valores aceitos\n");
    }
    else printf("Valores nao aceitos\n");
 
    return 0;
}

Comments

  1. UnknownJuly 31, 2017 at 10:50 AM

    plz tell me what is the problem of thid code

    #include
    using namespace std;
    int main()
    { int a,b,c,d,sum1,sum2;
    cin>>a>>b>>c>>d;
    sum1=c+d;
    sum2=a+b;
    if(b>c){
    if(d>a){
    if(sum1>sum2){
    if(c>0&&d>0){
    if(a%2==0){
    cout<<"Valores aceitos\n";
    }
    }

    }
    }

    }
    else{
    cout<<"Valores nao aceitos\n";
    }
    return 0;
    }

    ReplyDelete
  2. UnknownSeptember 11, 2017 at 5:26 AM

    This comment has been removed by the author.

    ReplyDelete
  3. Jiten Roy JonyJune 13, 2018 at 5:24 AM

    #include
    using namespace std;
    int main()
    {
    int A,B,C,D;
    cin>>A>>B>>C>>D;
    if(B>C && D>A)
    {
    if(C+D > A+B)
    {
    if(C>0 && D>0)
    {
    if(A%2==0)
    {
    cout<<"Valores aceitos"<<endl;
    }
    else
    {
    cout<<endl;
    }
    }
    else
    {
    cout<<endl;
    }
    }
    else
    {
    cout<<endl;
    }
    }
    else
    {
    cout<<"Valores nao aceitos"<<endl;
    }

    return 0;
    }

    why my code is got wrong answer 20%

    ReplyDelete
  4. UnknownMay 1, 2019 at 2:00 AM

    #include
    using namespace std;
    int main() {

    int a, b, c, d, sum;
    cin >> a >> b >> c >> d;

    if ((b > c) && (d > a) && ((c + d > a + b)) && (c&&d > 0) && (a % 2 == 0))
    cout << "Valores aceitos" << endl;
    else

    cout << "Valores nao aceitos" << endl;




    return 0;

    }

    ReplyDelete

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